Universidad Católica Boliviana "San Pablo"

x y z = A B C = 30 30.581 65.641 49.69 30.581 38.519 66.914 51.723 65.641 66.914 150.156 103.566 Resolviendo Ecuación x y z = A B C = Matriz inversa Matriz Resultado 30 30.581 65.641 49.69 0.9081 -0.1388 -0.3351 49.69 3.240 = A 30.581 38.519 66.914 51.72 = -0.1388 0.1361 0.0 x 51.72 = 0.145 = B 65.641 66.914 150.156 103.57 -0.3351 0.0 0.1532 103.57 -0.791 = C K = 1738.6287 m = 0.14504017 n = 0.79138518 T = [años] D = [min] Ecuación de Intencidad media = ∙ → = 1738,6287 ∙ 0,14504017 0,79138518 = = = 1 = 2 = ( ) = − UNIVERSIDAD CATOLICA "SAN PABLO" ________________________________________________________________________________________________________________ ANEXOS JOHN DEYBI CHINO CONDORI _________________________________________________________________________________________________________________ 14